Step 1. Your code, because of the -n, is all wrapped up in a loop. Which means that your "my $type = shift" statement will be executed each time through the loop. It also means that your $type is lexical to each time through the loop. Changing that line to: 

our $type;

BEGIN {
    $type ||= shift or die "no type";
}

[download]
solves that by creating $type as a global, and only setting it once (using ||=), and doing it before the loop (using BEGIN).

Step 2: fixing the regex. \w is "word" characters, which includes letters and numbers and the _. You probably want [[:alpha:]]. In which case, the total program looks like this: 

#!/usr/bin/perl -an

our $type;

BEGIN {
    $type ||= shift or die "no type";
}

if ( $type eq 'letters' ) {
  print if $_ =~ /[[:alpha:]]/;
} elsif ( $type eq 'numbers' ) {
  print if $_ =~ /\d/;
} else {
  print "bad type: $type"
}

[download]
Tested. Hope that helps.

PS: ++ - that's really a cool use for perl, too ;-)

In reply to Re: custom args with perl -an type invocation? by Tanktalus
in thread custom args with perl -an type invocation? by tphyahoo

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