You'd get the same output without the addition: 
my $float = 0.00;
print "$float\n"; # prints "0"

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Note that what you're doing when printing is coercing a number to a string. Perl's principle is to do this in the most basic way it can. If the number is technically a float internally, but its decimal expansion is .0000..., its string conversion will just look like an int. If you want it to look different, consider sprintf.

blokhead

In reply to Re: Integer vs Float during addition by blokhead
in thread Integer vs Float during addition by chrism01

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