Close, but no cigar :P

Remember, newlines within substitutions/matches that are modified by /x are ignored. Take out your '\n's and the de-obfuscated code "does the right thing", namely the last substitution finds a match, evaluates the substitution expression, which is an eval instruction which in turn evaluates the string "eval", contained by that time in $_, which leads to endless recursion. 

   MeowChow                                               
                print $/='"',(`$^X\144oc $^X\146aq1`)[-2]

In reply to Re: Re: Revisionism, Perl-Style by MeowChow
in thread Revisionism, Perl-Style by MeowChow

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