No bug. The statement parses as ($test ne 'c' ? ($OPER = 's') : $OPER) = 'c';
Jeff japhy Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and perl hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart

In reply to Re^2: ternary operator by japhy
in thread ternary operator by pglenski

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