Foreign? What do you call the units from which the Perl parse tree is made? That's to what I was refereing when I said bytecode. If anything, Perl code is more foreign than this code because perl can't execute Perl code without transforming it into this code first.

In reply to Re^5: encrypting perl code used with mod_perl by ikegami
in thread encrypting perl code used with mod_perl by moshkod

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