overload can do this, tie can't (though it's possible to also tie the array whose reference you want your object to pretend to contain). 
package Foo::Bar;
use strict;
use warnings;

my @aoa;
my $cnt;
sub new { bless \(my $obj_index = $cnt++) }
sub DESTROY { undef $aoa[${$_[0]}] }
use overload '@{}' => sub { $aoa[${$_[0]}] ||= [] }, fallback => 1;
1;

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In reply to Re: tie'ing a scalar as an array? (use overload, not tie) by ysth
in thread tie'ing a scalar as an array? by rvosa

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