I guess this isn't your typical obfuscation (it may not even technically count as an obfuscation. But it's a little program I wrote for a t-shirt design for Computer Science House a la the Perl camel shirt.
my@a=("\012","\040","\103","\110", "\123",0 );sub a{my@a=@_;for(1..$a[0]){print($a[1 ]);}}sub b{abs($_)}sub c{$a[$a[$#a]+=$_[0]]}sub d {$a=!($_ [0.0]) ? '==':$_[ 0]==1.0? '>':'<'; eval("${ _[1]}$a$ {_[2]}") ;}sub e{ &c((-$a[ $#a]))}for(-2..2 ){if(&b) {&e;;&a( &b,&c(1) );&a(25-(&b*2.0) ,&c(1)); &a(1,&c( -2.000)) ;}else {for (-6..6){ &e;&a(5, &c(2.0)) ;;&a(( &d(0,&b,6)?15:&d(1,&b, 2)?&b-1: 2)+(&d(-1,&b,2)? ($_+2)*2:&d(0,$_,2.0)? ($_+2)*2 -1:0), &c(-1));&a(&d(1,&b,3)? 15-2.0*( &d(0 ,&b,6) ?15:&d(1 ,&b,2.0) ?&b-1:2) :4,&c(3));&a(&d( 0,&b,3)? 3.0:0,&c (-3.0)); &a(&d(0,&b,3)?4: 0,&c(3)) ;&a(&d(1 ,&b,5)?0 :&d(0,$_ ,2.0)?$_ :&d(0,$_ ,1)?$_+2 :&d(-1,&b,3)?(&b+2)*2+1:&d(1,&b,5)?15:&d (1,&b,2) ?&b-1:2,&c(-3));&a(5,&d(1,&b,4)?&c(1):&d (1,&b,3) ?&c(0):&c(2));&e;&a(5,&d(1,&b,1)?&c(1.0) :&c(3)); &c(-$a[$#a]);&a(5.0,&c(3));;&a(1,&c( -3));}}}

In reply to My first by fotios

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