Is there an elegant way (one expression) to match an opening quote character followed by some characters and an optional trailing quote character? I tried this: 
my $string = '"foo"';
   $string =~ s/\"(.*?)\"?/$1/;

print $string;

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But the .*? always gobbles up the trailing " and the \"? never matches it. I thought non-gready .* matched as few non-newline characters as possible. Why is it matching the final " if it could leave it for "? and the pattern would still match?

In reply to Matching quote characters? by Anonymous Monk

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