If it did work, it would be (((undef) x 5), $hic) =, since ()x is a different operator than x, and the former is what you would want. But it doesn't in fact work: 
$ perl -we'(((undef) x 5), $foo) = 1..6; print $foo'
Can't modify repeat (x) in list assignment at -e line 1, near "6;"

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In reply to Re: undef and "x" operator by ysth
in thread undef and "x" operator by pglenski

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