I want to convert a cgi-app to fast-cgi, but there are lots of exit-statements deep in the code. This makes fast-cgi start the whole programm from the very beginning. Some kind of MyModule::exit would be possible, but what should MyModule::exit do? This is testcode I wrote to check it: 
#!/usr/bin/perl
use CGI::Fast qw(:standard);
our $COUNTER = 0;
while ( my $wwwform = CGI::Fast->new() ) {
    my $dinner = Dinner->new($wwwform);
    $dinner->serve( $COUNTER++ );
}

# Now the stuff long existing...

package Dinner;
use CGI::Fast qw(:standard);

sub new {
    my ( $class, $wwwform ) = @_;
    bless { wwwform => $wwwform }, $class;
}

sub serve {
    my ( $self, $counter ) = @_;
    print header, start_html('Fast CGI Test');
    printf "It's %s<br />", scalar localtime;
    print "Counter is $counter<br />";
    print end_html;

    # BAD! But in several parts of code...
    # Fastcgi-mainprogramm exits and starts to run on next
    # request from the very beginning, loading tons of modules
    # etc.
    exit;
    # Dinner::Base::exit() # ????
}
1;

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In reply to Fastcgi, howto deal with exit? by horshack

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