The handling of $_ is somewhat magical, and provided by the perl parser - not by the angle brackets. When perl sees this:
while (<>) { }
It actually does this:
while (defined($_ = <ARGV>)) { (); }
You can verify this yourself using B::Deparse. Here is an example (assume test.pl as filename):
perl -MO=Deparse test.pl
Problems:
  1. By adding the test for $i <= 4 to the while loop you caused perl to skip the magical behaviour for while(<>).
  2. You should chomp the data that is being read in, otherwise instead of "1" you will have "1\n"
Suggestions:
  1. It is a better practice to use push instead of (@arr1,$_)
  2. use warnings instead of perl -w

New version of the code that addresses the above

#!/usr/bin/perl use strict; use warnings; print "Enter 5 numbers: \n"; my $i=0; my @arr1=(); while (<>) { chomp; push @arr1, $_; last if ++$i > 4; } foreach my $m (@arr1) { print $m, "\n"; }

Update

Additionally, please read How To Ask A Question - Choose a Good, Descriptive Title

In reply to Re: Input to array from STDIN, then print, but print is not working by imp
in thread Input to array from STDIN, then print, but print is not working by Anonymous Monk

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