That was my initial thought but that would make 30 => 2 and not 1. So I think he wants int( ($num-1) / 30 ) + 1.

#!/usr/bin/perl

use strict;
use warnings;

my @nums = ( 1 .. 1000 );

foreach my $num ( @nums ) {
   my $test_n =  int( ($num-1) / 30 ) + 1;
   print "Num: $num - $test_n \n";
}

[download]

-derby

In reply to Re^2: condensing code by derby
in thread condensing code by Anonymous Monk

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