I agree that you probably don't want to use a variable as a variable name, but you still have to fix your problem. Have you considered using an array of arrays? You can define elements as $array[1][2]=(whatever) which would be the third element of the second array (0 being the first index).

In reply to Re^3: Adding a number from scalar variable to array name by hgolden
in thread Adding a number from scalar variable to array name by Anonymous Monk

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