If one has a reference and one wants to treat it like a regular variable then one cheap trick is to do this

$Href = {1=>1, 2=>2};
*H = $Href;   # aliases the referenced variable as a real variable
print $H{1};

[download]

But that's sort of evil, since one is actually creating a global variable %H not a lexical or local. If one has "use strict" turned on it will complain unless one declares "our %H";

So the question, oh great experts, is if it is possible to get this aliasing effect but with a lexical variable. Conceptually, I'd like to be able to write this:

use strict;
sub foo {
      my $Href = shift;
      my (%H);
      *H = $Href;   # define the alais  
      print $H{1};
}

[download]

But that does not work.

Something that does work, but once again uses globals, is to create a global, and then scope the alias inside the function using "local" like this:

use strict;
our %H;   #  have to create the global or local complains
sub foo {
      my $Href = shift;
      local (%H);  # instead of my use local
      *H = $Href;   # define the alias  
      print $H{1};
}

[download]

But now we are back to using global variables again which I don't like. Is there anyway to get an alias to the referenced variable that uses the lexical, scoped variables??

Code tags added by GrandFather

In reply to are TypeGlob assingments to a lexical variables possible? by cems22

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