Here's a succint but untested solution. If you're comparing lists or hashes of numbers, just replace eq with ==. If you don't like or don't understand Perl prototypes... well, too bad :)
# returns the largest element in a list
sub max(@) { (sort @_)[-1] }
# returns the union of two lists - i.e., all elements which are in at
+least one list
sub union(@@) { ++$f{$_} foreach (@{$_[0]}, @{$_[1]}); keys %f } }
# compares two list values for equality, by way of scalar(grep)
# note that it takes into account the possibility of lists of differen
+t sizes
sub lst_eq(@@) { scalar (grep { $_[0][$_] eq $_[1][$_] } (0..max ($#{$
+_[0]}, $#{$_[1]})) }
# compares two hashes for equality, by way of scalar(grep)
# note that it takes into account the possibility of hashes with diffe
+rent keys
sub hsh_eq(%%) { scalar (grep { $_[0]{$_} eq $_[1]{$_} } union (keys (
+%{$_[0]}), keys (%{$_[0]}))) }
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