huh.
@a = ('a%sc','b');
   printf @a;          # prints abc
print "\n";
   printf scalar @a;          # prints 2
print "\n";
   print sprintf @a;   # prints 2
print "\n";
  print sprintf @a[0,1]; # prints b
print "\n";
  print @a[0,1]; # prints a%scb
print "\n";
  print scalar @a[0,1]; # prints b
print "\n";
  print $a[1]; # prints b
print "\n";
  $huh = scalar @a[0,1]; # prints huhb
  print "huh", $huh;
print "\n";
  printf sprintf @a[0,1]; # prints b

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so sprintf evals in scalar (?) context, printf in array? Is there a why behind this?

a

In reply to Re: Re: printf vs. sprintf by a
in thread printf vs. sprintf by henrylaxen

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