$_[0] is actually a reference to the first argument passed by the caller.

I'm sure you know what you meant, but... $_[0] is (usually) an alias to the first argument. If it were a reference then you'd have to use ${$_[0]} or such.

- tye        

In reply to Re^4: shift vs @_ (alias) by tye
in thread shift vs @_ by Zadeh

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