There is no 'die' statement in the whole script

The thing is that there doesn't have to be a die statement or an explicit exit(255) in the script to get an exit value of 255. But something must be setting that value. As a (somewhat ridiculous) example, if you have a C compiler you could compile the following C program into 'try.exe':
int main(int argc, char * argv[]) { return 255; }

And then you could run the following perl script:
use warnings; my $ret = system("try.exe"); print $ret >> 8, "\n", $? >> 8, "\n";

You would find that produces as output:
255 255

In that perl script, there's no die(), no mention of "255" and, in fact, nothing even failed - yet the 8 high bits of $? were set. (Hopefully, you don't have an executable that's running successfully and returning 255.)

How do you find out what the exit code is ? Is there a 'print $exitcode;' in the script ? ... or a 'print $? >> 8;' ? ... If we know the means by which you are being made aware of the exit value, then that might help with our speculations.

Cheers,
Rob

In reply to Re^3: PERL exit code 255 by syphilis
in thread PERL exit code 255 by mcintst

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