Here's a way to do it in a regular expression. Note that there's no particular reason to use this instead of tr, except that it's kind of fun, and it will work as part of a larger pattern (for example to find any matching words within a paragraph). :-) 
/([perl]).*(?!\1)([perl]).*(?!\1)(?!\2)([perl]).*(?!\1)(?!\2)(?!\3)([p
+erl])/

[download]

This makes use of zero-width negative look-ahead assertions (see perlre(1)) to say essentially "any letters from this group, except for the ones you've already seen". So the first [perl] will match any of those four letters; the second time, it's preceded by an assertion that the character cannot be the character that matched the first time; and so forth.

Here's a variation that will pull out any words containing those four letters from a line of text: 

while (<>)
{
  my $i=0;
  print join(" ",
    grep { (($i++) % 5) == 0 } 
    /\b(([perl])\w*(?!\2)([perl])\w*(?!\2)(?!\3)([perl])\w*(?!\2)(?!\3
+)(?!\4)([perl]))\b/g),"\n";
}

[download]

--
sgifford's Web page

In reply to Re: A Quick Regex Question by sgifford
in thread A Quick Regex Question by chinamox

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