OK. that sounds good so far, but if I'm doing this in a looping context, and the next time around the loop, the values of @arrayB change, won't that change all of the references as well?
It depends on where @arrayB is declared.
my @arrayA; my @arrayB; while (...) { @arrayB = ...; push(@arrayA, \@arrayB); # XXX }
my @arrayA; my @arrayB; while (...) { @arrayB = ...; push(@arrayA, [ @arrayB ]); # Ok }
my @arrayA; while (...) { my @arrayB = ...; push(@arrayA, \@arrayB); # Ok }
my @arrayA; while (...) { my @arrayB = ...; push(@arrayA, [ @arrayB ]); # Needlessly creating 3rd array. }
Also, how could I save the anon array in your second example?
What does "save" mean? Copy? You already have a copy of the array in @arrayB.
In reply to Re^3: appending and array into last element of an array?
by ikegami
in thread appending and array into last element of an array?
by mdunnbass
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