Please notice that 
printem([@list1], [@list2]);

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actually creates two anonymous arrays and copy data in memory, while 
printem(\@list1, \@list2)

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will pass references to the original arrays.
Copying data will prevent accidental changes of the original arrays but may be quite long and memory-hungry if the copied data is big...
Here's a small sample to picture the difference : 
#!/usr/bin/perl


use strict;
use warnings;


use Data::Dumper;

my @list1 = qw(a b c);
my @list2 = qw(d e f);

sub sem {
  my $list1 = shift or die "no list1";
  my $list2 = shift or die "no list2";
  $list1->[0]='x';
  @{$list2}=qw(D E F);
}

# print original data
print "list1: " . Dumper(@list1);
print "list2: " . Dumper(@list2);

# call with copy 
sem([@list1], [@list2]);

print "list1: " . Dumper(@list1);
print "list2: " . Dumper(@list2);

# call by reference
sem(\@list1, \@list2);

print "list1: " . Dumper(@list1);
print "list2: " . Dumper(@list2);

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In reply to Re^2: How to pass two lists to a sub? by wazoox
in thread How to pass two arrays to a sub? by sanjay nayak

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