See update...ugh A nit perhaps, but...:

It would seem this shuffle guarantees that no element remains in it's current position. This seems less than random.

@array= sort { (-1,0,1)[int rand 3]} @array
I suspect you never see this type of thing because of the inefficiency. The cookbook example is making length(@foo) or less comparisons, the random sort is potentially doing more than length(@foo) comparisons.

Update: Hmm...my first statement, after further thought, appears to be silly.

In reply to Re: Re: help in understanding the standard array shuffle by kschwab
in thread help in understanding the standard array shuffle by Anonymous Monk

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