You are incorrect, the routine leaves open the possibility of keeping an item in place. Note the line next if ... there. In fact, as I recall it, that shuffle can be shown to have an even chance of producing any permutation with a true random source and is pretty damn good even with a really BAD random source.

Also, the rand trick you employ can exit early and leave chunks untouched. sortrather relies on consistency, if b>a and c>b then c>a should be implied. If I read the sort code right, violating that could lead to serious goofs like potentially never ending and such.

--
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In reply to Re: Re: Re: help in understanding the standard array shuffle by extremely
in thread help in understanding the standard array shuffle by Anonymous Monk

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