Sounds right. I just don't understand why a print() statement makes perl change its mind and use the correct instance of $x. Actually, I've been playing around with it and it seems like any reference to $x inside foo() makes it work correctly, even if it's just $x; on a line by itself.

In reply to Re^2: Doubly-nested deeply bound variable is undefined by asokoloski
in thread Doubly-nested deeply bound variable is undefined by asokoloski

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