I didn't even know you could call a subroutine from inside a regex.

The replace expression of the substitution operator is treated as Perl code rather than a string literal when the e modifier is used.

Ref: perlop

Just to be certain, the value for the match of /(\d+.\d+)/ is $1 and is then carried into sub convert as the value $_ ?

No. A subroutine's arguments are found in @_ (no relation to $_). $_[0] (again, no relation to $_) is the first element of @_, so it's the first argument of the subroutine.

Ref: perlsub


In reply to Re^3: Crafting a regex for a split() function... by ikegami
in thread Crafting a regex for a split() function... by chinamox

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