Are you sure $step is really a string (and not some kind of object with overloaded operators)? What does ref($step) return?

Also what's in $lupdate?

Normal string -> number conversion works: 

perl -e'my $step = "300"; print 10 % $step'
10

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In reply to Re: implicit numeric conversion isn't by Joost
in thread implicit numeric conversion isn't by stargrazer

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