Greetings Monks,
  My question is related to this post next'ing out of a "foreach" loop within a subroutine. Take this code: 
sub foo {
    my $param = shift;
    if ($param eq "skip") {
        next;
    }
}

foreach my $var (1, 2, 3, "skip", 4) {
    foo($var);
    print $var;
}

[download]
 I was expecting perl to throw me an error for using next to return from a sub{} , however it doesn't happen so. (although I could get a warning, if I use the -w flag). Also next, says: 
"next" cannot be used to exit a block which returns a value such as "eval {}", "sub {}" or "do {}"...

My question is: why this behaviour ? what is the logic behind it ? wouldn't it be beneficial if the interpreter threw a error for invalid use of next, in this case ? (I have tested this code under perl v5.8.6)

In reply to Exiting subroutine via next by InfiniteLoop

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