A slightly different, but not necessarily better, way would be to count the pipes using
tr, like this
my $numps = ($homes =~ tr{|}{});
and then find the "middle" one's position by using index in a loop
my $middle = int($numps / 2) + 1;
my $pos = -1;
my $found = 0;
while (1)
{
$pos = index $homes, q{|}, $pos;
last if ++ $found == $middle;
$pos ++;
}
substr $homes, $pos, 1, q{<BR>};
As you say, it is fun trying these things out. As for checking return values, I should perhaps check that index doesn't return -1 and that substr does return the pipe that I think I'm replacing; if this was production code I probably would :)
Cheers,
JohnGG
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