(Grrr. Lost a response. Shorter version follows)

I think this is a great analogy for illustrating the problem. However, consider the case where the sum must equal ten. There are only three options (4/6, 5/5, 6/4) and they occur with equal probability. However, we only see 4, 5 and 6, whereas the assumption was that the inputs could be evenly distributed between 1 and 6.

Does that matter? That's a question that requires the original problem context -- as you pointed out.

-xdg

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In reply to Re^6: Need technique for generating constrained random data sets by xdg
in thread Need technique for generating constrained random data sets by GrandFather

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