The solution posted by dragonchild is close. It just doesn't account for the fact that @selected_data has duplicate items in it. 

@selected_data = qw(13 76 90 13 77 100 76 300 13 65 400 74 89 34 65);
@all_data = qw(1 5 2 8 12 87 13 76 98 77 89 90 11 65 43 74 43 32 34 67
+);

my %all_hash; $all_hash{$_} = undef for @all_data;

my $total = scalar grep( exists $all_hash{ $_ }, @selected_data );
print "Count (kyle) -> $total\n";

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In reply to Re: Can I get better approach to get solution by kyle
in thread Can I get better approach to get solution by Anonymous Monk

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