If you add a column of 1's on the left (and a column of sums of 1 .. N after the 1..N column), you get Pascal's triangle, and thus the link to combinatorics:

1 1 1 1 1 1 1 1 1 1 1 2 3 4 5 6 7 8 9 10 1 3 6 10 15 21 28 36 45 55 1 4 10 20 35 56 84 120 165 220 1 5 15 35 70 126 210 330 495 715 1 6 21 56 126 252 462 792 1287 2002 1 7 28 84 210 462 924 1716 3003 5005 1 8 36 120 330 792 1716 3432 6435 11440

Update: added missing 3rd column as per eric256's observation

Fcn(D,N) => (5,10) seems to correspond to Choose(16,7) where Choose(n,k) is n!/k!(n-k)!

Likewise, Fcn(5,20) seems to correspond to Choose(26,7).

More generically, it looks like your function can be reduced to Choose(D+N+1,D+2)

Of course, you still have recursion in the computation of the factorial, so I don't think you can quite avoid it entirely.

-xdg

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In reply to Re^2: Math fun. by xdg
in thread Math fun. by BrowserUk

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