This is my entry on FizzBuzz: 
print+(Fizz)[$_%3].(Buzz)[$_%5]||$_,$/for 1..100

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or in words: since for any n multiple of 3 n % 3 == 0 I just make a list which has Fizz at index 0 and nothing else in it, and pull the (n%3)th element out of that list. Same for 5. Then I concatenate them together, print the result of that if it's true (not empty string), otherwise just n; then the default input record separator. Repeat for 1 to 100.

Straight forward and (almost) readable code (just add whitespace :-)

--shmem 

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

In reply to Re: Golf Challenge: FizzBuzz by shmem
in thread Golf Challenge: FizzBuzz by Ovid

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