I stumbled across 
    ($ret) ||= foo();

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today and wondered why foo() is in scalar context. I would have thought that the construct is equivalent to 
    ($ret) = $ret || foo();

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in which case foo() inherits the list context from the left side of the assignment.

Ideas?

In reply to Why are "a ||= b" and "a = a || b" different? by saintmike

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