I want to resolve a path like '/this/that/../instead/here/' to '/this/instead/here'.

Cwd::abs_path() will do it. It will also resolve symlinks. Which I foresee a possible problem with in the future, for what I am working on.

What I think I need is some way to resolve a path without resolving symlinks.. I looked at File::Spec::Functions 'canonpath', it cleans things up a bit- but that's all.

I was playing with the following script, but I don't trust my imperfect mind's ability to do this right..

use Test::Simple 'no_plan';
use strict;
#use File::Spec::Functions;
use constant DEBUG => 1;
my $p = {
# mess is      =>     should be
'/self/xplanatori' => '/self/xplanatori',
'/usr/lib/perl5/../../' => '/usr',
'/home/fake4/../fake/' => '/home/fake',
'/resolve/me/../right/' => '/resolve/right',
'/./resolve////me/../right/.' => '/resolve/right',
'/../.././usr/././.' => '/usr',
'/../.././////././.' => '/',
'/.....' => '/.....',
'.///../' =>'/'
};

#map { ok( canonpath($_) eq $p->{$_}, "$_" )   } keys %$p;

map { ok( abs_path2($_) eq $p->{$_}, "[$_]" )   } keys %$p;



sub abs_path2 {
    my $path = shift;
    print STDERR " [$path]\n" if DEBUG;

    $path=~s/(?<=\/)\.(?=\/|\z)/\//sg; # /./ or /. to /    
    print STDERR " [$path]\n" if DEBUG;

    1 while $path=~s/[^\/]+\/+\.\.[\/|\Z]*//g; # anything/../ to /
    print STDERR " [$path]\n" if DEBUG;

    
    $path=~s/\/{2,}/\//g; # /// to /
    $path=~s/(?<=.)\/+$//g; # a/ to a

    print STDERR " [$path]\n" if DEBUG;
    return $path;
}

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Any suggestions?

In reply to cleaning up absolute path without resolving symlinks by leocharre

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