$l_ref = \(1,2,3,4);
Here you are taking a reference to the result of evaluating the list (1,2,3,4) in scalar context, which is 4:
# perl -le '$l_ref = \(1,2,3,4); print $l_ref' SCALAR(0x8150310) # perl -le '$l_ref = \(1,2,3,4); print $$l_ref' 4

so you end up with an anonymous scalar holding the value 4.

You want to use

$l_ref = [ 1,2,3,4 ];

to create an anonymous array (or array reference).

A list is not a perl data type, it's just some grouping of elements, so you can't create a reference to that. You can only take a reference to what comes out of evaluating that grouping expression, which is not an array in your case, but the number of elements inside the list result of the comma operations inside the parens.

update: Corrected interpretation of what's inside the parens. Thanks, Anno.

--shmem

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

In reply to Re: Reference on List & Arrays Difference by shmem
in thread Reference on List & Arrays Difference by needperlhelp

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