I don't think this is the best way to solve the problem but, instead of ternaries, I thought I'd have a go with regex conditionals. It also uses an on-the-fly subroutine method suggested by
almut a couple of months ago
here.
use strict;
use warnings;
my $str = q{a,b=c,e=#f,ghi};
my @result =
map
{
my $res;
m
{(?x)
^
(?(?=([a-z])$)
(?{(sub {($res) = @_})->(qq{$1=>fn($1)})})
|
(?(?=([a-z])=([a-z])$)
(?{(sub {($res) = @_})->(qq{$2=>$3})})
|
(?(?=([a-z])=\#([a-z])$)
(?{(sub {($res) = @_})->(qq{$4=>fn($5)})})
|
(?{(sub {($res) = @_})->(q{???})})
)
)
)
};
$res
}
split m{,}, $str;
print qq{@result\n};
It prints
a=>fn(a) b=>c e=>fn(f) ???
I hope this is of interest.
Cheers,
JohnGG
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