So it actually spits a warning the first time.

Where does that warning go? It's not on my screen when I run it. As I see it, $output is uninitialized both times, but the warning is not printed the first time.

I'm confused also because what I pass to open is a reference to $output which is always a real value regardless of whether $output is initialized or not.

In reply to Re^2: Use of uninitialized value in open second time but not first. by kyle
in thread Use of uninitialized value in open second time but not first. by kyle

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