Just for the record, there's syntax oddity in your example code. $str =~ trim($str); isn't really doing anything. Your output from this would be: 

   Hello

[download]

The =~ assignment is used to assign a string to a regular expression. It is not assignment of one scalar to another. In this case, I don't think it even calls the trim function. I've modified the example to return the expected result: 

use strict;

sub trim($)
{
    my $string = shift;
    $string =~ s/^\s+//;
    $string =~ s/\s+$//;
    return $string;
}


my $str = "   Hello     ";
$str = trim($str);
print $str; #"Hello"

[download]

Hazah! I'm Employed!

In reply to Re: Removing white-lines... by osunderdog
in thread Removing white-lines... by pyro.699

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