After that, I think it should work.
I disagree (I may be wrong). Consider exists:
Given an expression that specifies a hash element or array element, returns true if the specified element in the hash or array has ever been initialized, even if the corresponding value is undefined.
In reply to Re^2: Hash checking
by shigetsu
in thread Hash checking
by Anonymous Monk
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |