No,
$1 will
not be
undef if the match fails. The only time they are undefined is when a match has not yet been done, or a match does not contain a captured pattern for that variable:
#!/usr/bin/perl -w
if ("abc" =~ /(\w+)/, 1) { print "abc => $1\n" }
{
print "local: $1\n";
if ("ghi" =~ /\w+/, 1) { print "ghi => $1\n" }
if ("def" =~ /(\w+)/, 1) { print "def => $1\n" }
if ("[=]" =~ /(\w+)/, 1) { print "[=] => $1\n" }
}
print "general: $1\n";
__END__
abc => abc
local: abc
Use of uninitialized value at regexes line 6.
ghi =>
def => def
[=] => def
general: abc
However, a failed match returns false, so if you removed the
, 1's from each of those, you wouldn't see the line for "
=".
japhy --
Perl and Regex Hacker
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