The ampersand & marks the following { } construct as a code block; the backslash disambiguates that operation from binary '&' (the bitwise AND) and returns a reference for that code block.

It's not really a code block. \&{foo} is a reference to the subroutine with the name "foo". Similarly, \& { print "foo" } is a reference to the subroutine with the name that is returned by print, i. e. it's \&1 (unless print fails).

$ perl -lwe 'my $code = \&{print "foo"}' foo $ perl -lwe 'my $code = \&{print "foo"}; $code->()' foo Undefined subroutine &main::1 called at -e line 1.

(Note that $code is not called/dereferenced in the first one-liner, yet it prints foo.


In reply to Re^2: Mr. Ternary is greater than Mrs. If Else by betterworld
in thread Mr. Ternary is greater than Mrs. If Else by PerlPhi

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