You have quotes inside your quotes. Try the following:

print $sh->ls( qq(-l ./logs/ |grep -v "^d" |grep -v file1 | awk 'NR>1 
+{ print \$9}'));

[download]

Or indeed you could use q() as you're not doing any variable substitution inside the string.

Update: yes I know it would be better for the OP to have coded this in perl rather than shelling out 4 subprocesses. Sometimes you need to start with where the person is. Spotting the quote nesting is something glaringly obvious to me - a kind of mistake anyone can make in coding, and worth pointing out.

--
wetware hacker
(Qualified NLP Practitioner and Hypnotherapist)

In reply to Re: Shell Commands executed in perl script by rinceWind
in thread Shell Commands executed in perl script by msk_0984

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