It's six of one and a half dozen of the other, I suppose, but I would prefer to dispense with the unwanted first line another way.

$ ls -l
total 4
-rw-r--r--   1 root     root           0 May 22 21:09 accts
drwxr-xr-x   2 root     root         512 May 22 21:10 dir1
-rw-r--r--   1 root     root           0 May 22 21:09 file1
-rw-r--r--   1 root     root           0 May 22 21:09 file1.log
-rw-r--r--   1 root     root           0 May 22 21:09 file13
-rw-r--r--   1 root     root           0 May 22 21:09 fred
drwxr-xr-x   2 root     root         512 May 22 21:10 staff
$ perl -Mstrict -Mwarnings -e '
> open my $lsFH, q{-|}, q{ls -l}
>    or die $!;
> scalar <$lsFH>;
> print
>    map  { qq{@{ [ (split)[8] ] }\n} }
>    grep { m{^[^d]} && ! m{file1} }
>    <$lsFH>;'
accts
fred
$

[download]

Using a filehandle and a scalar read gets rid of the first line before the loop and avoids the extra test each time in the grep.

Cheers,

JohnGG

In reply to Re^2: Shell Commands executed in perl script by johngg
in thread Shell Commands executed in perl script by msk_0984

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