"@_ is a reference, and change its value will be seen in the calling func"

Er - NO. From perldoc perlsub

The array @_ is a local array, but its elements are aliases for the actual scalar parameters.

So, you are wrong on 2 counts:

Perhaps what you meant to say was - what trips perl newbies is that fact that the ELEMENTS of @_ are aliased to the caller's parameters - hence changing an ELEMENT of @_ would modify the caller's variable.

     "An undefined problem has an infinite number of solutions." - Robert A. Humphrey         "If you're not part of the solution, you're part of the precipitate." - Henry J. Tillman

In reply to Re^2: Why does assignment change the result? by NetWallah
in thread Why does assignment change the result? by Anonymous Monk

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