So your saying that if operation evaluation order (associativity) is specified, but operand evaluation order is not specified, 

$result = foo() - bar() - baz() - moo();

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could be evaluated as 

$anon1 = moo();
$anon2 = baz();
$anon3 = bar();
$anon4 = foo();

$result = (($anon4 - $anon3) - $anon2) - $anon1;

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I suppose you're right and it doesn't violate the definition of associativity, but how odd!

In reply to Re^7: eval order of args to a sub by ikegami
in thread eval order of args to a sub by otto

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