This was posted as an untested solution to a SOPW a week or so past and it was stated by a monk that there was indeed an error in the calculations. Can someone provide a working solution keeping my methods thus far intact? I know it can be done via Image::Image or another module but those aren't available in my workspace and I'd like to see how close I got to the final solution.
The question was: the user needed a way to determine the h/w of an image and output an html-resized version of it so that both h/w are less than a max value.. AND the image has to stay the same aspect ratio.
#!/usr/bin/perl
use warnings;
use strict;
my $height = "1000";
my $width = "1234";
my $maxh = "600";
my $maxw = "800";
if ($height > $maxh || $width > $maxw)
{
my $hratio = $height / $maxh;
my $wratio = $width / $maxw;
my $newh = $height / $hratio;
my $neww = $width / $hratio;
print "Height is now $newh, Width is now $neww";
}
RESPONSE FROM ALMUT:
It's not quite as trivial as it might seem at first (most of us who ha
+ve tried probably got it wrong the first time :)
Just as an example, take a width of 1000 and a height of 100. Your al
+gorithm would compute 6000x600 (W x H), although the expected result
+would be 800x80 (i.e. max width doesn't exceed 800 and aspect ratio s
+tays at 10:1)
"Age is nothing more than an inaccurate number bestowed upon us at birth as just another means for others to judge and classify us"
sulfericacid
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