But it's getting in your way here. You'll need to set up the hash as a series of actions, not as an initialization.my $this = $this * 2; # use outer $this to initialize local inner $thi +s
-- Randal L. Schwartz, Perl hacker
In reply to Re: Re-using a hash value in same hash?
by merlyn
in thread Re-using a hash value in same hash?
by oakley
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