Essentially, you're worried about details you don't need to worry about. At a guess, when you do an "execute", the information isn't loaded into perl's memory yet, but rather will (usually) be sitting in a buffer inside the database itself. Once you do a "fetchall" of some sort, then the entire result set is definitely loaded into perl's memory, and for efficiency's sake what you want is to get a reference to that datastructure, you don't want to make a second copy of it just to save you from thinking about references.

You understand, that when you do a: 

   $working_href = $returned_href;

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that's just making a copy of a scalar value, but if you do a: 
   %working = %returned;

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that makes a copy of the entire data-structure. That doubles you memory usage, and wastes time in making the copy... so you don't want to do that unless you have a really good reason (like you're planning on modifying the copy and you need to preserve the original).

By the way, if you need to join an array given a reference to it, you just do this: 

   my $string = join " ", @{ $aref };

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There's no "extra step" you need to do.

In reply to Re^3: Why a reference, not a hash/array? by doom
in thread Why a reference, not a hash/array? by Cody Pendant

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