This would do the trick: 
#!/usr/bin/perl -w
%hash=( 89=>3, 45=>2, 1 =>5, 40=>3);
foreach (sort { $a <=> $b } keys(%hash) )
{
    print "key: $_ value: $hash{$_}\n"
}

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Jouke Visser, Perl 'Adept'

In reply to Re: how do i sort hash by key numerically by Jouke
in thread how do i sort hash by key numerically by Anonymous Monk

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