The $& is not set on the redone block. Look at perlre

The numbered match variables ($1, $2, $3, etc.) and the related punctuation set ($+ , $& , $` , $' , and $^N ) are all dynamically scoped until the end of the enclosing block or until the next successful match, whichever comes first.

This block should give the behavior you were expecting, by storing the $& from the previous run.

#!/usr/bin/perl
use strict;
use warnings;
my $b;
for( $_ = "fred"; s/(.)//; ) {
    $b = $& if $&;
    print "I saw the character [$b]\n";
    redo if $b eq 'e';
}

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In reply to Re: Does redo create a new dynamic scope? by neosamuri
in thread Does redo create a new dynamic scope? by brian_d_foy

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